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Thursday, 18 January 2018
Learn C language Part -40 SQL ORACLE DATABASE STRUCTURE IN C LANGUAGE
#include <stdio.h>
#include <conio.h>
#include <string.h>
struct employee
{
int id ;
char name[50];
float salary;
char department[50] ;
};
main()
{
int i;
struct employee e1[5];
e1[0].id=101;
strcpy(e1[0].name,"Ali");
e1[0].salary=50000;
strcpy(e1[0].department,"HR");
//2ND RECORD..........................
e1[1].id=102;
strcpy(e1[1].name,"BILAL");
e1[1].salary=60000;
strcpy(e1[1].department,"IT");
//3rd RECORD..........................
e1[2].id=103;
strcpy(e1[2].name,"Daniyal");
e1[2].salary=40000;
strcpy(e1[2].department,"Marketing");
//3rd RECORD..........................
e1[3].id=104;
strcpy(e1[3].name,"Eraj");
e1[3].salary=30000;
strcpy(e1[3].department,"Admin");
//4th RECORD..........................
e1[4].id=105;
strcpy(e1[4].name,"faisal");
e1[4].salary=20000;
strcpy(e1[4].department,"Admin");
l1:
printf("\nID\tName\t\tSalary\t\tDepatment\t\n\n");
for(i=0;i<5;i++)
{
printf("\n-----------------------------------------------------------\n");
printf("%d\t%s\t\t%.2f\t\t%s\t",e1[i].id,e1[i].name,e1[i].salary,e1[i].department);
printf("\n");
}
printf("\n-----------------------------------------------------------\n");
printf("Enter the id: ");
int n;
scanf("%d",&n);
for(i=0;i<5;i++)
{
if(e1[i].id==n)
{
printf("\nID\tName\t\tSalary\t\tDepatment\t\n\n");
printf("\n-----------------------------------------------------------\n");
printf("%d\t%s\t\t%.2f\t\t%s\t",e1[i].id,e1[i].name,e1[i].salary,e1[i].department);
printf("\n");
n=-1;
break;
}
}
if(n!=-1)
{
printf("\n No Records found......");
}
printf("\nDo you want to continue......{y/n}\n");
char c;
scanf("%c",&c);
c=getchar();
if(c=='y')
{
printf("\n\n");
goto l1;
}
}
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